Last updated on July 16th, 2025
We use the derivative of e^sin(x), which combines the properties of the exponential and trigonometric functions, as a tool to measure how this complex function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now discuss the derivative of e^sin(x) in detail.
We now understand the derivative of e^sinx. It is commonly represented as d/dx (e^sinx) or (e^sinx)', and its value is e^sinx * cosx.
The function e^sinx has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Exponential Function: (e^x), where e is the base of natural logarithms.
Chain Rule: Rule for differentiating e^sinx because it is a composition of functions.
Trigonometric Functions: sin(x) and cos(x) are used in the derivative.
The derivative of e^sinx can be denoted as d/dx (e^sinx) or (e^sinx)'.
The formula we use to differentiate e^sinx is: d/dx (e^sinx) = e^sinx * cosx
The formula applies to all x, as the exponential function and sine function are continuous everywhere.
We can derive the derivative of e^sinx using proofs. To show this, we will use the chain rule along with the properties of exponential and trigonometric functions.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of e^sinx results in e^sinx * cosx using the above-mentioned methods:
Using Chain Rule To prove the differentiation of e^sinx using the chain rule, We use the formula: Let u = sinx, then e^u = e^sinx
By the chain rule: d/dx [e^u] = e^u * du/dx u = sinx, so du/dx = cosx
Therefore, d/dx (e^sinx) = e^sinx * cosx Using Product Rule We will now prove the derivative of e^sinx using the product rule.
The step-by-step process is demonstrated below:
Here, we use the formula, Let y = e^sinx y = e^u, where u = sinx
The product rule formula: d/dx [u.v] = u'.v + u.v'
Since v = e^sinx is not a product, we use the chain rule as shown earlier.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
o understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes.
Higher-order derivatives make it easier to understand functions like e^sinx. For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of e^sinx, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is π/2, the derivative is e^sin(π/2) * 0 = 0 because cos(π/2) = 0. When x is 0, the derivative of e^sinx = e^0 * 1 = 1.
Students frequently make mistakes when differentiating e^sinx. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (e^sinx * ln(x))
Here, we have f(x) = e^sinx * ln(x).
Using the product rule, f'(x) = u′v + uv′ In the given equation, u = e^sinx and v = ln(x).
Let’s differentiate each term, u′ = d/dx (e^sinx) = e^sinx * cosx v′ = d/dx (ln(x)) = 1/x Substituting into the given equation, f'(x) = (e^sinx * cosx) * ln(x) + (e^sinx) * (1/x)
Let’s simplify terms to get the final answer, f'(x) = e^sinx * cosx * ln(x) + e^sinx/x
Thus, the derivative of the specified function is e^sinx * cosx * ln(x) + e^sinx/x.
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
XYZ Corporation measures a quantity represented by the function y = e^sin(x), where y represents a varying concentration at a distance x. If x = π/3 meters, calculate the rate of change of concentration.
We have y = e^sin(x) (concentration function)...(1)
Now, we will differentiate the equation (1) Take the derivative of e^sin(x): dy/dx = e^sin(x) * cos(x)
Given x = π/3, substitute this into the derivative: dy/dx = e^sin(π/3) * cos(π/3) dy/dx = e^(√3/2) * 1/2
Hence, we get that the rate of change of concentration at x = π/3 is (e^(√3/2)) / 2.
We find the rate of change of concentration at x = π/3 as (e^(√3/2)) / 2, indicating the rate at which concentration changes at this specific point.
Derive the second derivative of the function y = e^sin(x).
The first step is to find the first derivative, dy/dx = e^sin(x) * cos(x)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [e^sin(x) * cos(x)]
Here we use the product rule, d²y/dx² = (d/dx [e^sin(x)]) * cos(x) + e^sin(x) * (d/dx [cos(x)])
d²y/dx² = (e^sin(x) * cos(x)) * cos(x) + e^sin(x) * (-sin(x))
d²y/dx² = e^sin(x) * cos²(x) - e^sin(x) * sin(x)
Therefore, the second derivative of the function y = e^sin(x) is e^sin(x) * (cos²(x) - sin(x)).
We use the step-by-step process, where we start with the first derivative. Using the product rule, we differentiate e^sin(x) * cos(x). We then substitute the identity and simplify the terms to find the final answer.
Prove: d/dx (e^(2sin(x))) = 2e^(2sin(x)) * cos(x).
Let’s start using the chain rule: Consider y = e^(2sin(x))
To differentiate, we use the chain rule: dy/dx = e^(2sin(x)) * d/dx (2sin(x)) = e^(2sin(x)) * 2cos(x)
Substituting y = e^(2sin(x)), d/dx (e^(2sin(x))) = 2e^(2sin(x)) * cos(x)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace 2sin(x) with its derivative. As a final step, we substitute y = e^(2sin(x)) to derive the equation.
Solve: d/dx (e^sinx/x)
To differentiate the function, we use the quotient rule: d/dx (e^sinx/x) = (d/dx (e^sinx) * x - e^sinx * d/dx(x))/x²
We will substitute d/dx (e^sinx) = e^sinx * cosx and d/dx (x) = 1 (e^sinx * cosx * x - e^sinx * 1) / x² = (x * e^sinx * cosx - e^sinx) / x²
Therefore, d/dx (e^sinx/x) = (x * e^sinx * cosx - e^sinx) / x²
In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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